C++ Program to Store and Display Information Using Structure

In this program, a structure, student is created.

This structure has three members: name (string), roll (integer) and marks (float).

Then, we created a structure array of size 10 to store information of 10 students.

Using for loop, the program takes the information of 10 students from the user and displays it on the screen.

Example: Store Information in Structure and Display it

#include <iostream>
using namespace std;

struct student
{
    char name[50];
    int roll;
    float marks;
} s[10];

int main()
{
    cout << "Enter information of students: " << endl;

    // storing information
    for(int i = 0; i < 10; ++i)
    {
        s[i].roll = i+1;
        cout << "For roll number" << s[i].roll << "," << endl;

        cout << "Enter name: ";
        cin >> s[i].name;

        cout << "Enter marks: ";
        cin >> s[i].marks;

        cout << endl;
    }

    cout << "Displaying Information: " << endl;

    // Displaying information
    for(int i = 0; i < 10; ++i)
    {
        cout << "\nRoll number: " << i+1 << endl;
        cout << "Name: " << s[i].name << endl;
        cout << "Marks: " << s[i].marks << endl;
    }

    return 0;
}

Output

Enter information of students: 

For roll number1,
Enter name: Tom
Enter marks: 98

For roll number2,
Enter name: Jerry
Enter marks: 89
.
.
.
Displaying Information:

Roll number: 1
Name: Tom
Marks: 98
.
.
.

Also Read:

• C++ Program to Store Information of a Student in a Structure